A point charge Q of mass 8.50 g hangs from the horizontal ceiling by a light 25.0-cm thread.When a horizontal electric field of magnitude 1750 N/C is turned on,the charge hangs away from the vertical as shown in the figure.The magnitude of Q is closest to

Question

Quizplus · Accepted Answer

The force of gravity acting on the charge is given by:
Fg = mg = (8.50 x 10^-3 kg) x (9.81 m/s^2) = 0.0832 N

The force of the electric field on the charge is given by:
Fe = Q*E = Q*(1750 N/C)

Since the charge is in equilibrium, the two forces must balance each other out:
Fe = Fg

Q*(1750 N/C) = 0.0832 N

Q = 0.0832 N / (1750 N/C) = 4.76 x 10^-5 C = 47.6 µC

Therefore, the magnitude of Q is closest to choice letter A, 27.5 µC.

A Point Charge Q of Mass 8