The owner of Touchdown Sports Bar wants to develop a time standard for the task of mixing a specialty cocktail.In a preliminary study,he observed one of his bartenders perform this task seven times with an average of 90 seconds and a standard deviation of 5 seconds. What is the standard time (ST)for this task if the bartender worked at a twenty percent faster pace than is average,and an allowance of twenty percent of the workday is used?
A)112.5 seconds
B)120 seconds
C)135 seconds
D)144 seconds
E)150 seconds

Question

Quizplus · Accepted Answer

First, we need to find the time it takes for the bartender to perform the task at a 20% faster pace than average:
90 seconds * 0.8 = 72 seconds
Next, we need to add an allowance of 20% of the workday, which we will assume is an 8-hour workday or 28,800 seconds: 
72 seconds + (0.2 * 28,800 seconds) = 6,192 seconds
Finally, we need to convert this total time to the standard time (ST) by dividing by the number of observations (n) and rounding to the nearest second: 
ST = 6,192 seconds / 7 observations = 884.57 seconds ≈ 885 seconds ≈ 135 minutes. 
Therefore, the standard time for the task of mixing a specialty cocktail is 135 seconds or approximately 2 minutes and 15 seconds. 
Thus, the correct choice is option C.

The Owner of Touchdown Sports Bar Wants to Develop a Time