The owner of Touchdown Sports Bar wants to develop a time standard for the task of mixing a specialty cocktail.In a preliminary study,he observed one of his bartenders perform this task seven times with an average of 90 seconds and a standard deviation of 5 seconds. What is the standard time (ST)for this task if the bartender worked at a twenty percent faster pace than is average,and an allowance of ten percent of job time is used?
A)135 seconds
B)123.8 seconds
C)118.8 seconds
D)120 seconds
E)112.5 seconds

Question

Quizplus · Accepted Answer

Step 1: Calculate the new average time taken by the bartender.
New average time = (1+20/100)*90 seconds = 108 seconds

Step 2: Calculate the standard time (ST) using the following formula:
ST = Average time + Allowance
Allowance = 10% of Average time

Substituting the values in the formula, we get:
ST = 108 seconds + 10% of 108 seconds
ST = 118.8 seconds

Therefore, the standard time (ST) for the task of mixing a specialty cocktail is 118.8 seconds, which is closest to option C (118.8 seconds).

The Owner of Touchdown Sports Bar Wants to Develop a Time