What is the output of the following code fragment?
Int f1int base, int limit)
{
Ifbase > limit)
Return -1;
Else
Ifbase == limit)
Return 1;
Else
Return base * f1base+1, limit) ;
}
Int main)
{
Cout << f112,4) <<endl;
Return 0;
}

Question

What is the output of the following code fragment?
Int f1int base, int limit)
{
Ifbase > limit)
Return -1;
Else
Ifbase == limit)
Return 1;
Else
Return base * f1base+1, limit);
}
Int main)
{
Cout << f112,4)<<endl;
Return 0;
}
A) 2
B) 3
C) -1
D) 6

Quizplus · Accepted Answer

The function `f1` is designed to recursively multiply numbers from `base` up to `limit`. However, the code provided has syntax errors and won't compile as is. Assuming the intent was to write a correct recursive function and the question is about the logic, the function will return -1 when called with `f1(2, 4)` because the base case for returning -1 is when `base > limit`, which is not true for the given call. The correct logic, assuming the syntax errors (like missing types and incorrect symbols) were fixed and interpreting the intent, would lead to a calculation instead. But based on the given code and its direct outcome, the answer is -1 due to the condition check at the beginning of the function.

What Is the Output of the Following Code Fragment