If NodeTypePtr is defined to be a pointer type to a node in a linked list, then the declaration
NodeTypePtr head;
A) allocates memory for the node that head will point to
B) automatically makes head-link point to NULL
C) allocates only the memory for a pointer variable
D) allocates a linked list

Question

If NodeTypePtr is defined to be a pointer type to a node in a linked list, then the declaration
NodeTypePtr head;
A) allocates memory for the node that head will point to
B) automatically makes head->link point to NULL
C) allocates only the memory for a pointer variable
D) allocates a linked list

Quizplus · Accepted Answer

The declaration "NodeTypePtr head;" only allocates memory for a pointer variable, not for a node or a linked list. It simply creates a pointer variable named "head" that can point to a node in a linked list. The memory for the actual node(s) in the list must be allocated separately, either by dynamically creating new nodes with malloc() or by using a pre-existing node(s) as the head of the list.

If NodeTypePtr Is Defined to Be a Pointer Type to a Node