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Suppose you have a population of flour beetles with 1,000 individuals.Normally the beetles are red;however,this population is polymorphic for a mutant autosomal body color,black,designated by bb.Red is dominant to black,so BB and Bb genotypes are red.Assume the population is at Hardy-Weinberg equilibrium,with equal frequencies of the two alleles.
-What would be the allele frequencies if a population bottleneck occurred and only four individuals survived: one female red heterozygote and three black males?
A) 0.125 red;0.875 black
B) 0.875 red;0.125 black
C) 0.25 red;0.75 black
D) 0.75 red;0.25 black
E) 0.5 red;0.5 black

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Quizplus · Accepted Answer

The allele frequencies in the original population are p = q = 0.5. After the bottleneck, the allele frequencies are determined by the genotypes of the four survivors. The female is heterozygous, so she contributes one B allele and one b allele to the gene pool. The three males are all homozygous black, so they each contribute one b allele to the gene pool. Therefore, the gene pool after the bottleneck contains 1 B allele and 7 b alleles. The allele frequencies are therefore p = 1/8 = 0.125 and q = 7/8 = 0.875.

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