Assume that you have an urn containing 10 balls of the following description:
4 are white (W)and lettered (L)
2 are white (W)and numbered (N)
3 are yellow (Y)and lettered (L)
1 is yellow (Y)and numbered (N)
If you draw a numbered ball (N),the probability that this ball is white (W)is 0.667.

Question

Quizplus · Accepted Answer

To find the probability of drawing a white ball given that it is numbered, we need to use conditional probability. Let's denote the event of drawing a white ball with W and the event of drawing a numbered ball with N. We want to find P(W|N), which is the probability of drawing a white ball given that it is numbered. We know from the problem that P(N|W) = 2/6 (since there are 2 white numbered balls out of a total of 6 numbered balls) and P(W) = 6/10 (since there are 6 white balls out of a total of 10 balls). Using Bayes' rule, we have:

P(W|N) = P(N|W)*P(W)/P(N)

where P(N) is the probability of drawing a numbered ball, regardless of color. We can find P(N) as follows:

P(N) = P(N|W)*P(W) + P(N|Y)*P(Y) 
     = 2/6*6/10 + 1/4*4/10 
     = 7/20

Substituting the values we have found, we get:

P(W|N) = (2/6*6/10)/(7/20) = 0.667

Therefore, the answer is A: True.

Assume That You Have an Urn Containing 10 Balls of the Following