TABLE 9-6
The quality control engineer for a furniture manufacturer is interested in the mean amount of force necessary to produce cracks in stressed oak furniture.She performs a two-tail test of the null hypothesis that the mean for the stressed oak furniture is 650.The calculated value of the Z test statistic is a positive number that leads to a p-value of 0.080 for the test.
-True or False: Referring to Table 9-6,suppose the engineer had decided that the alternative hypothesis to test was that the mean was greater than 650.Then if the test is performed with a level of significance of 0.05,the null hypothesis would be rejected.

Question

Quizplus · Accepted Answer

The p-value is greater than the level of significance, so the null hypothesis would not be rejected. However, if the alternative hypothesis was that the mean was greater than 650, then the p-value would be compared to the level of significance for a one-tail test, which is 0.025. In this case, the p-value would be less than the level of significance, so the null hypothesis would be rejected.

TABLE 9-6 The Quality Control Engineer for a Furniture Manufacturer Is Interested