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Phenylketonuria is considered to be an inborn error of metabolism.It is a recessive genetic condition in which the enzyme that breaks down the amino acid phenylalanine is defective or missing.Testing of all newborns allows this condition to be detected at birth.A special diet that severely minimizes phenylalanine (e.g. ,by avoiding diet sodas and most usual sources of protein)can treat the condition.
In this scenario,two carriers of both cystic fibrosis and phenylketonuria have a child.
What is the probability that the child will have both cystic fibrosis and phenylketonuria?

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Quizplus · Accepted Answer

Since both cystic fibrosis and phenylketonuria are inherited in an autosomal recessive manner, each parent has a 1 in 4 chance (25%) of passing on the defective gene for each condition to their child. To find the probability of the child inheriting both conditions, multiply the probabilities for each condition: 1/4 (for cystic fibrosis) * 1/4 (for phenylketonuria) = 1/16, which equals 6.25%.

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