The cross GE/ge X ge/ge produces the following progeny: GE/ge 404,ge/ge 396,gE/ge 97,Ge/ge 103.From these data,one can conclude that there are 20 map units between the G and E loci.

Question

Quizplus · Accepted Answer

The crossing over frequency between two loci is proportional to the distance between them. In this case, the total number of progeny is 1000 (sum of all four types), and half of them have recombination between G and E loci (97 + 103 = 200). Therefore, the recombination frequency is 200/1000 = 0.2 or 20%. Since one map unit is equal to 1% recombination frequency, the distance between the two loci is 20 map units.

The Cross GE/ge X Ge/ge Produces the Following Progeny: GE/ge