In a population of 100 individuals,49 percent are of the NN blood type.What percentage is expected to be MN assuming Hardy-Weinberg equilibrium conditions?
A)9 percent
B)21 percent
C)42 percent
D)51 percent
E)There is insufficient information to answer this question.

Question

Quizplus · Accepted Answer

Under Hardy-Weinberg equilibrium conditions, the frequency of the MN genotype can be calculated using the equation:

p^2 + 2pq + q^2 = 1

where p and q are the frequencies of the two alleles (in this case, N and M), and pq is the frequency of the MN genotype.

If 49% of the individuals are NN, then the frequency of the N allele is 0.7 (the square root of 0.49). Therefore, the frequency of the M allele is 0.3.

Plugging these values into the equation above, we get:

(0.7)^2 + 2(0.7)(0.3) + (0.3)^2 = 0.49 + 0.42 + 0.09 = 1

So the frequency of the MN genotype is 2pq = 0.42 or 42%. Therefore, the answer is C.

In a Population of 100 Individuals,49 Percent Are of the NN