If the random variable X is exponentially distributed with parameter $\lambda$ = 4,then the probability P(X $\le$0.25),up to 4 decimal places,is
A) 0.6321
B) 0.3679
C) 0.2500
D) None of these choices.

Question

Quizplus · Accepted Answer

The cumulative distribution function (CDF) for an exponential distribution with parameter λ is given by P(X ≤ x) = 1 - e^(-λx). Substituting λ = 4 and x = 0.25, we get P(X ≤ 0.25) = 1 - e^(-4 * 0.25) = 1 - e^(-1) ≈ 0.6321.

If the Random Variable X Is Exponentially Distributed with Parameter λ\lambdaλ

If the Random Variable X Is Exponentially Distributed with Parameter $\lambda$