Retries
The following table contains the probability distribution for X = the number of retries necessary to successfully transmit a 1024K data package through a double satellite media.
$$\begin{array} { | c | c c c c | }
\hline \boldsymbol { x } & 0 & 1 & 2 & 3 \
\hline \boldsymbol { p } ( \boldsymbol { x } ) & 0.35 & 0.35 & 0.25 & 0.05 \
\hline
\end{array}$$
-If X and Y are two variables with $$\sigma _ { x } ^ { 2 } = 12.25$$ , $\sigma _ { y } ^ { 2 } = 17.64$ ,and COV(X,Y)= 11.76,then the coefficient of correlation $\sigma$ = 0.8.

Question

Retries
The following table contains the probability distribution for X = the number of retries necessary to successfully transmit a 1024K data package through a double satellite media.
 $$\begin{array} { | c | c c c c | } 
\hline \boldsymbol { x } & 0 & 1 & 2 & 3 \
\hline \boldsymbol { p } ( \boldsymbol { x } ) & 0.35 & 0.35 & 0.25 & 0.05 \
\hline
\end{array}$$
-If X and Y are two variables with $$\sigma _ { x } ^ { 2 } = 12.25$$ , $\sigma _ { y } ^ { 2 } = 17.64$ ,and COV(X,Y)= 11.76,then the coefficient of correlation $\sigma$ = 0.8.

Quizplus · Accepted Answer

Since the coefficient of correlation is calculated as COV(X,Y) / (SD(X)*SD(Y)), we can plug in the given values to find:
ρ = 11.76 / (sqrt(12.25)*sqrt(17.64)) = 0.8
Therefore, the statement is true.

Retries the Following Table Contains the Probability Distribution for X

Retries
the Following Table Contains the Probability Distribution for X