Cars
Suppose X = the number of cars owned by a family in the U.S.The probability distribution of X is shown in the table below.
$\begin{array}{|l|c|c|c|c|}
\hline X & 0 & 1 & 2 & 3 \
\hline \text { Probability } & 0.56 & 0.23 & 0.12 & 0.09 \
\hline
\end{array}$
-{Cars Narrative} Suppose you choose two families at random.What is the chance that they each own one car? (That means family A owns a car and family B owns a car. )
A) 0.23
B) 0.23 + 0.23 = 0.46
C) 0.23 + 0.23 - (0.23)*(0.23)= .4071
D) (0.23)*(0.23)= 0.0529

Question

Cars
Suppose X = the number of cars owned by a family in the U.S.The probability distribution of X is shown in the table below.
 $\begin{array}{|l|c|c|c|c|}
\hline X & 0 & 1 & 2 & 3 \
\hline \text { Probability } & 0.56 & 0.23 & 0.12 & 0.09 \
\hline
\end{array}$ 
-{Cars Narrative} Suppose you choose two families at random.What is the chance that they each own one car? (That means family A owns a car and family B owns a car. )
A) 0.23
B) 0.23 + 0.23 = 0.46
C) 0.23 + 0.23 - (0.23)*(0.23)= .4071
D) (0.23)*(0.23)= 0.0529

Quizplus · Accepted Answer

The probability that one family owns one car is 0.23. Since the families are chosen at random and with replacement, the probability of the second family also owning one car is also 0.23.
The probability of both events happening (independent events) is the product of the individual probabilities, which is (0.23)*(0.23) = 0.0529. Therefore, the answer is D.

Cars Suppose X = the Number of Cars Owned by a Family

Cars
Suppose X = the Number of Cars Owned by a Family