E'° of the NAD⁺/NADH Half Reaction Is -0 $\rightarrow$ Oxaloacetate + NADH + H⁺

E'° of the NAD⁺/NADH half reaction is -0.32 V.The E'° of the oxaloacetate/malate half reaction is
-0) 175 V.When the concentrations of NAD⁺,NADH,oxaloacetate,and malate are all 10^-5 M,the "spontaneous" reaction is:

A) malate + NAD⁺ $\rightarrow$ oxaloacetate + NADH + H⁺.
B) malate + NADH + H⁺ $\rightarrow$ oxaloacetate + NAD⁺.
C) NAD⁺ + NADH + H⁺ $\rightarrow$ malate + oxaloacetate.
D) NAD⁺ + oxaloacetate $\rightarrow$ NADH + H⁺ + malate.
E) oxaloacetate + NADH + H⁺ $\rightarrow$ malate + NAD⁺.