During transfer of two electrons through the mitochondrial respiratory chain, the overall reaction is: NADH + 1/2 O₂ + H⁺ $\rightarrow$ NAD⁺ + H₂O For this reaction, the difference in reduction potentials for the two half-reactions ($\Delta$E'°) is +1.14 V. Show how you would calculate the standard free-energy change, $\Delta$G'°, for the reaction. (The Faraday constant, , is 96.48 kJ/V · mol.)

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The Answer of During transfer of two electrons through the mitochondrial respiratory chain, the overall reaction is: NADH + 1/2 O₂ + H⁺ $\rightarrow$ NAD⁺ + H₂O For this reaction, the difference in reduction potentials for the two half-reactions ($\Delta$E'°) is +1.14 V. Show how you would calculate the standard free-energy change, $\Delta$G'°, for the reaction. (The Faraday constant, , is 96.48 kJ/V · mol.)

During Transfer of Two Electrons Through the Mitochondrial Respiratory Chain →\rightarrow→

During Transfer of Two Electrons Through the Mitochondrial Respiratory Chain $\rightarrow$