Light enters water (n = 1.33) from air. The incident light ray makes a 0.44$\degree$ angle with the normal to the surface on the air side. What will be the angle made with the normal by the refracted ray on the water side?

Question

Quizplus · Accepted Answer

Using Snell's Law, $ n_1 \sin(\theta_1) = n_2 \sin(\theta_2) $, where $ n_1 = 1 $ (air), $ \theta_1 = 0.44\degree $, and $ n_2 = 1.33 $ (water), we find $ \theta_2 \approx 0.33\degree $.

Light Enters Water (N = 1 °\degree° Angle with the Normal to the Surface on the Air

Light Enters Water (N = 1 $\degree$ Angle with the Normal to the Surface on the Air