You have exactly 4 resistors: one 3$\Omega$, one 4$\Omega$, one 5$\Omega$, and one 6$\Omega$. How can you combine these to make a 2$\Omega$ resistor? (The symbol$\Omega$ stands for "ohm.")
A) Connect the 3$\Omega$ resistor in series with the 5$\Omega$ resistor.
B) Connect the 3$\Omega$ resistor in parallel with the 6$\Omega$ resistor.
C) Connect the 3$\Omega$ resistor in parallel with the 4$\Omega$ resistor.
D) Connect all four resistors in parallel with each other.
E) You can't make a 2$\Omega$ resistor from the ones listed.

Question

Quizplus · Accepted Answer

When resistors are connected in parallel, their equivalent resistance is given by the formula 1/R(eq) = 1/R(1) + 1/R(2) + ... 1/R(n), where R(1), R(2), ..., R(n) are the resistances of the individual resistors. 
Using this formula, we can calculate the equivalent resistance of the 3 F1F1F1S1F1F1F10 resistor and 6 F1F1F1S1F1F1F10 resistor when connected in parallel as: 1/R(eq) = 1/3 + 1/6 = 1/2, which means the equivalent resistance is equal to 2 F1F1F1S1F1F1F10. 
Therefore, choice B is the best choice for combining the given resistors to obtain a 2 F1F1F1S1F1F1F10 resistor.

You Have Exactly 4 Resistors: One 3 Ω\OmegaΩ , One 4 Ω\OmegaΩ

You Have Exactly 4 Resistors: One 3 $\Omega$ , One 4 $\Omega$