Consider the horizontal parallel plates. The upper plate has a voltage difference of 30 V with the lower plate, and they are separated by 3 cm. You move the two plates carefully to a separation of 4 cm. What is the strength of the electric field between the plates?
A) 3000 volts/meter
B) 1000 volts/meter
C) 750 volts/meter
D) 7.5 volts/meter

Question

Quizplus · Accepted Answer

The electric field strength between two plates is given by the voltage difference divided by the separation distance. Initially, the electric field strength is $ \frac{30\,V}{3\,cm} = \frac{30\,V}{0.03\,m} = 1000\,V/m $. When the separation is increased to 4 cm (or 0.04 m), the electric field strength becomes $ \frac{30\,V}{0.04\,m} = 750\,V/m $.

Consider the Horizontal Parallel Plates