A heat engine takes in 500 J of energy from the hot reservoir in one cycle while performing 100 J of work. The amount of heat transferred to the cold reservoir in the same time is

Question

Quizplus · Accepted Answer

According to the first law of thermodynamics, the total energy input to the engine (500 J) is used to perform work (100 J) and to transfer heat to the cold reservoir (let's call this Qc). Therefore, we can write:
500 J = 100 J + Qc
Solving for Qc, we get:
Qc = 400 J
So the correct answer is (B), 400 J.

A Heat Engine Takes in 500 J of Energy from the Hot