The temperature of a 50 g sample of aluminum is raised from 20^oC to 60^oC when 440 cal of heat are added. The specific heat capacity of the aluminum is A) not calculable from this data. B) 0.11 cal/g C^o. C) 15.4 cal/g C$\degree$. D) 0.91 cal/g C$\degree$. E) 0.22 cal/g C$\degree$.

Question

Quizplus · Accepted Answer

The specific heat capacity (c) can be calculated using the formula: c = Q / (m * ΔT), where Q is the heat added (440 cal), m is the mass (50 g), and ΔT is the change in temperature (60°C - 20°C = 40°C). Plugging in the values, c = 440 cal / (50 g * 40°C) = 0.22 cal/g°C.

The Temperature of a 50 G Sample of Aluminum Is °\degree°

The Temperature of a 50 G Sample of Aluminum Is $\degree$