The density of aluminum is 2700 kg/m³. An aluminum block has a mass of 2.5 kg. The buoyant force exerted on this block when it is completely submerged in water of density 1000 kg/m³ is approximately A) 0.0091 N. B) 0.93 N. C) 2.5 N. D) 9.1 N. E) 24.5 N.

Question

Quizplus · Accepted Answer

First, we need to find the volume of the aluminum block:

Density = mass/volume
Volume = mass/density
Volume = 2.5 kg / 2700 kg/m^3 = 0.0009259 m^3

Next, we can use Archimedes' principle to find the buoyant force:

Buoyant force = weight of water displaced
Weight of water displaced = density of water x volume of block x gravitational acceleration
Weight of water displaced = 1000 kg/m^3 x 0.0009259 m^3 x 9.81 m/s^2
Weight of water displaced = 9.065 N

Therefore, the buoyant force exerted on the block is approximately 9.1 N (rounded to one significant figure). The answer is D.

The Density of Aluminum Is 2700 Kg/m3

The Density of Aluminum Is 2700 Kg/m³