In a population of 100 individuals,49% are of the NN blood type.What percentage is expected to be MN assuming Hardy- Weinberg equilibrium conditions?

Question

Quizplus · Accepted Answer

Under Hardy-Weinberg equilibrium conditions, the frequency of the MN blood type can be calculated using the equation: 
p^2 + 2pq + q^2 = 1 
where p is the frequency of the N allele and q is the frequency of the M allele. 
Given that 49% of the population is NN, we know that p = 0.49. 
Therefore, q can be found by taking the square root of (1 - p^2): 
q = sqrt(1 - 0.49^2) ≈ 0.867 
Next, we can calculate the expected frequency of MN individuals as 2pq: 
2(0.49)(0.867) ≈ 0.848 
So, approximately 84.8% of the population is expected to be MN. However, since this question is asking for the percentage rather than frequency, we need to multiply by 100 to get the final answer: 
0.848 x 100 ≈ 84.8% ≈ 42%. Therefore, the best choice is B.

In a Population of 100 Individuals,49% Are of the NN