When its brakes are applied, a car moving at 10 m/s undergoes an acceleration of -1.2 m/s². How far does the car travel before it comes to a stop? A) 42 m B) 78 m C) 83 m D) 124 m

Question

Quizplus · Accepted Answer

The car's stopping distance can be calculated using the formula $d = \frac{v^2}{2a}$, where $v = 10 \, \text{m/s}$ is the initial velocity and $a = -1.2 \, \text{m/s}^2$ is the acceleration. Plugging in the values, $d = \frac{10^2}{2 \times 1.2} = \frac{100}{2.4} = 41.67 \, \text{m}$, which rounds to 42 meters, making option A correct.

When Its Brakes Are Applied, a Car Moving at 10