A 300-g ball is struck with a bat with a force of 150 N. If the bat was in contact with the ball for 0.02 s, the ball flew off at
A) 0.01 m/s.
B) 0.1 m/s.
C) 2.5 m/s.
D) 10 m/s.

Question

Quizplus · Accepted Answer

The change in velocity of the ball can be calculated using the impulse-momentum theorem, which states that the impulse (force times time) equals the change in momentum (mass times change in velocity). The impulse here is 150 N * 0.02 s = 3 Ns. The mass of the ball is 300 g or 0.3 kg. Using the formula, impulse = mass * change in velocity, we get 3 = 0.3 * change in velocity, solving for change in velocity gives us 10 m/s.

A 300-G Ball Is Struck with a Bat with a Force