A 1200-kg car is traveling at 10 m/s on a road such that the maximum frictional force between its tires and the road is 4000 N. The minimum turning radius of the car is
A) 15 m.
B) 30 m.
C) 60 m.
D) 120 m.

Question

Quizplus · Accepted Answer

The minimum turning radius can be found using the formula for centripetal force, $ F = \frac{mv^2}{r} $, where $ F $ is the frictional force (4000 N), $ m $ is the mass of the car (1200 kg), $ v $ is the velocity (10 m/s), and $ r $ is the radius of the turn. Rearranging the formula to solve for $ r $, we get $ r = \frac{mv^2}{F} $. Plugging in the given values, $ r = \frac{1200 \times 10^2}{4000} = 30 $ meters.

A 1200-Kg Car Is Traveling at 10 M/s on a Road