The latent heat of melting is 80 calories for 1 gram of ice. If 1 gram of ice absorbs 120 calories, what is the result?
A) 1 gram of water at a temperature of 40°C
B) a mixture of water and steam at a temperature of 120°C
C) a mixture of ice and water at a temperature of 0°C
D) 1 gram of water at a temperature of 120°C
E) 1 gram of water at a temperature of 20°C

Question

Quizplus · Accepted Answer

The latent heat of melting is the amount of heat required to convert 1 gram of ice to 1 gram of water at 0°C without changing its temperature. Since 80 calories are needed to melt the ice, the remaining 40 calories (120 - 80) will raise the temperature of the water. Given that the specific heat capacity of water is 1 calorie/g°C, the 40 calories will increase the temperature of the 1 gram of water by 40°C, resulting in 1 gram of water at a temperature of 40°C.

The Latent Heat of Melting Is 80 Calories for 1