Given that s is a String, what does the following loop do? for(int j = s.length(); j 0; j--)
System.out.print;
A) It prints s out backwards
B) It prints s out forwards
C) It prints s out backwards after skipping the last character
D) It prints s out backwards but does not print the first character
E) It yields a run-time error because there is no character at s.charAt(j-1) for j = 0

Question

Given that s is a String, what does the following loop do? for(int j = s.length(); j > 0; j--)
System.out.print;
A) It prints s out backwards
B) It prints s out forwards
C) It prints s out backwards after skipping the last character
D) It prints s out backwards but does not print the first character
E) It yields a run-time error because there is no character at s.charAt(j-1) for j = 0

Quizplus · Accepted Answer

The loop iterates through the string `s` from the last character to the first, printing each character in reverse order. The condition `j > 0` ensures that the loop stops before `j` becomes 0, avoiding an out-of-bounds error when accessing `s.charAt(j-1)`.

Given That S Is a String, What Does the Following