Which product would be expected in the hydrogenation of 3-methylhept-3-ene with excess hydrogen gas using a palladium catalyst?

Question

Quizplus · Accepted Answer

Hydrogenation of an alkene, like 3-methylhept-3-ene, using a palladium catalyst and excess hydrogen gas, results in the addition of hydrogen across the double bond, converting the alkene into an alkane. Since the reaction does not create or destroy chiral centers, the product is not optically active. Therefore, the product is 3-methylheptane, which is not chiral, making the concept of (R) or (S) configuration irrelevant. The process does not produce a racemic mixture because the product is achiral.

Which Product Would Be Expected in the Hydrogenation of 3-Methylhept-3-Ene