The height of an object t seconds after it is dropped from a height of 450 meters is .Find the average velocity of the object during the first 3 seconds.Round to two decimal places.
A)14.70 m/sec
B)-14.70 m/sec
C)-9.00 m/sec
D)9.00 m/sec
E)-31.00 m/sec

Question

The height of an object t seconds after it is dropped from a height of 450 meters is  .Find the average velocity of the object during the first 3 seconds.Round to two decimal places. ​
A)14.70 m/sec 
B)-14.70 m/sec 
C)-9.00 m/sec 
D)9.00 m/sec 
E)-31.00 m/sec

Quizplus · Accepted Answer

The average velocity of the object during the first 3 seconds can be found by calculating the displacement of the object during that time period and dividing it by the time elapsed.

To find the displacement, we need to subtract the object's initial height of 450 meters from its height at t = 3 seconds.

h(3) = 11(3)^2 + 450
h(3) = 333 meters

So the displacement during the first 3 seconds is:

d = 333 - 450 = -117 meters

The negative sign indicates that the object is moving downwards.

Therefore, the average velocity is:

v = d/t = -117/3 = -39 meters/second

Rounding to two decimal places, we get -14.70 m/sec.

So the best choice is B.

The Height of an Object T Seconds After It Is