In a two-point cross to map genes A and B,you obtained 98 recombinant types and 902 parental types among the offspring.How far apart are these genes?
A)9.8 cM
B)0)98 cM
C)90.2 cM
D)9.02 cM
E).098 cM

Question

Quizplus · Accepted Answer

The distance between genes is calculated as the number of recombinant offspring divided by the total number of offspring, multiplied by 100 to convert to centimorgans (cM). Here, (98 recombinants / 1000 total offspring) * 100 = 9.8 cM.

In a Two-Point Cross to Map Genes a and B,you