In rabbits,there is a gene that controls ear length,with a dominant allele "T" for long ears and a recessive allele "t" for short ears.At another gene locus,there are alleles "B" for black coat and "W" for white coat.Neither the B or W allele is dominant,and BW produces a gray coat.These two allele pairs assort independently.If a gray rabbit that is heterozygous at the gene locus controlling ear length is mated with a white rabbit that is also heterozygous at the gene locus controlling ear length,what proportion of the long-eared offspring will be homozygous for the long-eared trait?
A)1/8
B)1/4
C)1/3
D)1/2

Question

Quizplus · Accepted Answer

The gray rabbit has the genotype B/W T/t, and the white rabbit has the genotype W/W T/t. When considering only the ear length gene, the possible genotypes for the offspring are TT, Tt, and tt. Since we're only interested in long-eared offspring (TT or Tt), the TT genotype represents 1/3 of the long-eared offspring (TT or Tt), as the possible combinations are TT, Tt, and Tt, with TT being the only homozygous long-eared genotype.

In Rabbits,there Is a Gene That Controls Ear Length,with a Dominant