One product of the reaction of sodium and water is sodium hydroxide.What mass of sodium is needed to make 2.0 L of 0.075 M NaOH(aq)?

Question

Quizplus · Accepted Answer

To find the mass of sodium needed to make 2.0 L of 0.075 M NaOH, first calculate the moles of NaOH required using the molarity formula (Moles = Molarity × Volume). Here, 0.075 M × 2.0 L = 0.15 moles of NaOH are needed. The reaction between sodium and water produces sodium hydroxide according to the equation: 2 Na + 2 H2O → 2 NaOH + H2. From this equation, it's clear that 2 moles of Na produce 2 moles of NaOH, meaning the mole ratio of Na to NaOH is 1:1. Therefore, 0.15 moles of Na are needed to produce 0.15 moles of NaOH. The molar mass of sodium (Na) is approximately 23 g/mol, so the mass of sodium needed is 0.15 moles × 23 g/mol = 3.45 g, which rounds to 3.4 g.

One Product of the Reaction of Sodium and Water Is