Complete the following nuclear decay reaction. ${ }_{88}^{221} \mathrm{Ra} \rightarrow+{ }_{2}^{4} \mathrm{He}$

Question

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The decay described is an alpha decay, where a nucleus emits an alpha particle (${ }_{2}^{4} \mathrm{He}$). Subtracting the mass and atomic numbers of the alpha particle from those of the original radium (${ }_{88}^{221} \mathrm{Ra}$) nucleus gives ${ }_{86}^{217} \mathrm{Rn}$.

Complete the Following Nuclear Decay Reaction 88221Ra→+24He{ }_{88}^{221} \mathrm{Ra} \rightarrow+{ }_{2}^{4} \mathrm{He}88221​Ra→+24​He

Complete the Following Nuclear Decay Reaction ${ }_{88}^{221} \mathrm{Ra} \rightarrow+{ }_{2}^{4} \mathrm{He}$