Given the following half-reactions, Pb(s) + 2I−(aq) → PbI₂(s) + 2e−
I₂(aq) + 2e− → 2I−(aq) Write the balanced overall reaction.

Question

Given the following half-reactions, Pb(s)+ 2I−(aq)→ PbI₂(s)+ 2e− I₂(aq)+ 2e− → 2I−(aq) Write the balanced overall reaction.

Quizplus · Accepted Answer

The two half-reactions can be combined by reversing the second reaction and multiplying it by 2, then adding the two half-reactions together to cancel out the electrons. This gives the overall reaction: Pb(s) + 2I-(aq) + 2Hg2+(aq) -> PbI2(s) + 2Hg(l)

Given the Following Half-Reactions, Pb(s)+ 2I−(aq)→ PbI2(s)+ 2e−

Given the Following Half-Reactions, Pb(s)+ 2I−(aq)→ PbI₂(s)+ 2e−