Calculate the equilibrium constant for the following reaction at 25°C, 2IO₃^-(aq) + 5Hg(l) + 12H⁺(aq) ? I₂(s) + 5Hg²⁺(aq) + 6H₂O(l) Given the following thermodynamic information.(R = 8.31 J/K?mol,F = 96480 C/mol e?) z
$\begin{array}{ll}\mathrm{IO}_{3}{ }^{-}(a q) +6 \mathrm{H}^{+}(a q) +5 e^{-} \rightarrow \mathrm{I}_{2}(s) +3 \mathrm{H}_{2} \mathrm{O}(l) & E^{\circ}=+1.20 \mathrm{~V} \\\mathrm{Hg}^{2+}(a q) +2 e^{-} \rightarrow \mathrm{Hg}(l) & E^{\circ}=+0.86 \mathrm{~V}\end{array}$

Question

Calculate the equilibrium constant for the following reaction at 25°C, 2IO₃^-(aq) + 5Hg(l) + 12H⁺(aq) ? I₂(s) + 5Hg²⁺(aq) + 6H₂O(l) Given the following thermodynamic information.(R = 8.31 J/K?mol,F = 96480 C/mol e?) z

\begin{array}{ll}\mathrm{IO}_{3}{ }^{-}(a q) +6 \mathrm{H}^{+}(a q) +5 e^{-} \rightarrow \mathrm{I}_{2}(s) +3 \mathrm{H}_{2} \mathrm{O}(l) & E^{\circ}=+1.20 \mathrm{~V} \\\mathrm{Hg}^{2+}(a q) +2 e^{-} \rightarrow \mathrm{Hg}(l) & E^{\circ}=+0.86 \mathrm{~V}\end{array}

Quizplus · Accepted Answer

The Answer of Calculate the equilibrium constant for the following reaction at 25°C, 2IO₃^-(aq)+ 5Hg(l)+ 12H⁺(aq)? I₂(s)+ 5Hg²⁺(aq)+ 6H₂O(l) Given the following thermodynamic information.(R = 8.31 J/K?mol,F = 96480 C/mol e?)z $\begin{array}{ll} \mathrm{IO}_{3}{ }^{-}(a q)+6 \mathrm{H}^{+}(a q)+5 e^{-} \rightarrow \mathrm{I}_{2}(s)+3 \mathrm{H}_{2} \mathrm{O}(l) & E^{\circ}=+1.20 \mathrm{~V} \ \mathrm{Hg}^{2+}(a q)+2 e^{-} \rightarrow \mathrm{Hg}(l) & E^{\circ}=+0.86 \mathrm{~V} \end{array}$

Calculate the Equilibrium Constant for the Following Reaction at 25°C