Calculate E for the following electrochemical cell at 25°C,
Cu | Cu²⁺ (0.100 M) || Zn²⁺ (0.0750 M) | Zn
If E° (Cu²⁺) = +0.339 V and E° (Zn²⁺) = −0.762 V.(R = 8.31 J/K⋅mol,F = 96480 C/mol e−)

Question

Quizplus · Accepted Answer

The correct answer is A because the overall cell reaction is:Cu2+ + Zn → Cu + Zn2+The standard cell potential is:E°cell = E°(Cu2+/Cu) + E°(Zn2+/Zn) = +0.339 V + (-0.762 V) = -0.423 VThe cell potential at nonstandard conditions is:Ecell = E°cell - (RT/nF)ln(Q) = -0.423 V - (8.31 J/K⋅mol * 298 K / (2 * 96480 C/mol e−)) * ln(0.100 / 0.0750) = -1.105 V

Calculate E for the Following Electrochemical Cell at 25°C