The K_sp of barium chromate is 1.2 × 10−¹⁰.What is the concentration of Ba²⁺ in equilibrium with BaCrO₄(s)if [CrO₄²⁻] = 4.3 × 10−³ M?

Question

Quizplus · Accepted Answer

The solubility product expression for barium chromate is Ksp = [Ba²⁺][CrO₄²⁻]. Given Ksp = 1.2 × 10⁻¹⁰ and [CrO₄²⁻] = 4.3 × 10⁻³ M, solve for [Ba²⁺]: [Ba²⁺] = Ksp / [CrO₄²⁻] = (1.2 × 10⁻¹⁰) / (4.3 × 10⁻³) = 2.8 × 10⁻⁸ M.

The Ksp of Barium Chromate Is 1

The K_sp of Barium Chromate Is 1