Consider the reaction Cu(OH)₂(s)+ 4NH₃(aq) ? Cu(NH₃)₄²⁺(aq)+ 2OH?(aq) K = 4 × 10?⁷ If the K_f for Cu(NH₃)₄²⁺ is 1 × 10¹²,what is the value of K_sp for Cu(OH)₂?

Question

Quizplus · Accepted Answer

The value of $K_{sp}$ for $Cu(OH)_2$ can be calculated using the given equilibrium constant $K$ and the $K_f$ for $Cu(NH_3)_4^{2+}$. Since $K = \frac{K_{sp}}{K_f}$, rearranging gives $K_{sp} = K \times K_f = 4 \times 10^{-17} \times 1 \times 10^{12} = 4 \times 10^{-5}$.

Consider the Reaction Cu(OH)2(s)+ 4NH3(aq) ? Cu(NH3)42+(aq)+ 2OH?(aq)

Consider the Reaction Cu(OH)₂(s)+ 4NH₃(aq) ? Cu(NH₃)₄²⁺(aq)+ 2OH?(aq)