Determine the heat of evaporation of carbon disulfide, CS₂(l) ? CS₂(g)
Given the enthalpies of reaction below.
$\begin{array}{ll}\mathrm{C}(s) +2 \mathrm{~S}(s) \rightarrow \mathrm{CS}_{2}(l) & \Delta H=+89.4 \mathrm{~kJ} \\\mathrm{C}(s) +2 \mathrm{~S}(s) \rightarrow \mathrm{CS}_{2}(g) & \Delta H=+116.7 \mathrm{~kJ}\end{array}$

Question

Determine the heat of evaporation of carbon disulfide, CS₂(l) ? CS₂(g)
Given the enthalpies of reaction below.

\begin{array}{ll}\mathrm{C}(s) +2 \mathrm{~S}(s) \rightarrow \mathrm{CS}_{2}(l) & \Delta H=+89.4 \mathrm{~kJ} \\\mathrm{C}(s) +2 \mathrm{~S}(s) \rightarrow \mathrm{CS}_{2}(g) & \Delta H=+116.7 \mathrm{~kJ}\end{array}

Quizplus · Accepted Answer

The heat of evaporation of carbon disulfide can be found by subtracting the enthalpy of formation of liquid CS2 from the enthalpy of formation of gaseous CS2. Thus, $+116.7 \, \text{kJ} - (+89.4 \, \text{kJ}) = +27.3 \, \text{kJ}$.

Determine the Heat of Evaporation of Carbon Disulfide, CS2(l)? CS2(g)

Determine the Heat of Evaporation of Carbon Disulfide, CS₂(l)? CS₂(g)