Which Is a Correct Method for Calculating the Moles of Calcium

Which is a correct method for calculating the moles of calcium carbonate present in 132 grams of calcium carbonate?

A) $132 \mathrm{~g} \mathrm{CaCO}_{3}\left(\frac{6.022 \times 10^{23} \text { atoms }}{1 \mathrm{~mol}}\right) \left(\frac{100.1 \mathrm{~mol}}{1 \mathrm{~g}}\right)$
B) $132 \mathrm{~g} \mathrm{CaCO}_{3}\left(\frac{1 \mathrm{~mol}}{100.1 \mathrm{~g}}\right)$
C) $132 \mathrm{~g} \mathrm{CaCO}_{3}\left(\frac{100.1 \mathrm{~g}}{1 \mathrm{~mol}}\right)$
D) $132 \mathrm{~g} \mathrm{CaCO}_{3}\left(\frac{100.1 \mathrm{~mol}}{1 \mathrm{~g}}\right)$
E) none of the above