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Which Is a Correct Method for Determining the Total Number

Question 4

Multiple Choice

Which is a correct method for determining the total number of atoms in 123 grams of sulfur trioxide (SO3) ?


A) 123 g SO3(1 mol80.07 g) (1 atom 6.022×1023 mol) 123 \mathrm{~g} \mathrm{~SO}_{3}\left(\frac{1 \mathrm{~mol}}{80.07 \mathrm{~g}}\right) \left(\frac{1 \text { atom }}{6.022 \times 10^{23} \mathrm{~mol}}\right)
B) 123 g SO3(1 mol80.07 g) (6.022×1023 atoms 1 mol) 123 \mathrm{~g} \mathrm{~SO}_{3}\left(\frac{1 \mathrm{~mol}}{80.07 \mathrm{~g}}\right) \left(\frac{6.022 \times 10^{23} \text { atoms }}{1 \mathrm{~mol}}\right)
C) 123 g SO3(1 mol80.07 g) (1 molatoms4 mol SO3) (6.022×1023 atoms 1 mol) 123 \mathrm{~g} \mathrm{~SO}_{3}\left(\frac{1 \mathrm{~mol}}{80.07 \mathrm{~g}}\right) \left(\frac{1 \mathrm{~mol} \mathrm{atoms}}{4 \mathrm{~mol} \mathrm{~SO}_{3}}\right) \left(\frac{6.022 \times 10^{23} \text { atoms }}{1 \mathrm{~mol}}\right)
D) 123 g SO3(1 mol80.07 g) (4 mol atoms 1 molSO3) (1 atom 6.022×1023 mol) 123 \mathrm{~g} \mathrm{~SO}_{3}\left(\frac{1 \mathrm{~mol}}{80.07 \mathrm{~g}}\right) \left(\frac{4 \mathrm{~mol} \text { atoms }}{1 \mathrm{~mol} \mathrm{SO}_{3}}\right) \left(\frac{1 \text { atom }}{6.022 \times 10^{23} \mathrm{~mol}}\right)
E) 123 g SO3(1 mol80.07 g) (4 molatoms1 molSO3) (6.022×1023 atoms 1 mol) 123 \mathrm{~g} \mathrm{~SO}_{3}\left(\frac{1 \mathrm{~mol}}{80.07 \mathrm{~g}}\right) \left(\frac{4 \mathrm{~mol} \mathrm{atoms}}{1 \mathrm{~mol} \mathrm{SO}_{3}}\right) \left(\frac{6.022 \times 10^{23} \text { atoms }}{1 \mathrm{~mol}}\right)

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