How many liters of 0.2805 M C₆H₁₂O₆(aq)contain 1.000 g of C₆H₁₂O₆?

Question

Quizplus · Accepted Answer

Firstly, we need to calculate the number of moles of C₆H₁₂O₆ present in 1.000 g. Molar mass of C₆H₁₂O₆= $12.01+32.06+1.0079+112.11+15.999+32.06+15.999+16.00=237.24$ g/mol Number of moles = $\frac{1.000 ext{ g}}{237.24 ext{ g/mol}}=0.004214$ mol Now, we can use the formula: Molarity = $\frac{ ext{Number of moles}}{ ext{Volume (in L)}}$ Rearranging this formula to solve for volume gives: Volume = $\frac{ ext{Number of moles}}{ ext{Molarity}}$ Plugging in the values: Volume = $\frac{0.004214 ext{ mol}}{0.2805 ext{ mol/L}} = 0.01979$ L = 19.79 mL Therefore, the answer is B with a volume of 0.01979 L.

How Many Liters of 0