The combustion of glucose (C₆H₁₂O₆) with oxygen gas produces carbon dioxide and water. This process releases 2803 kJ per mole of glucose. When 3.00 mol of oxygen react in this way with glucose, what is the energy release in kcal? (Hint: Write a balanced equation for the combustion process.)

Question

Quizplus · Accepted Answer

The balanced equation for the combustion of glucose is:

C6H12O6 + 6O2 → 6CO2 + 6H2O

From the equation and the given information, we can see that 1 mole of glucose reacts with 6 moles of oxygen and releases 2803 kJ of energy. Therefore, 3.00 mol of oxygen will react with 0.5 mol of glucose (since we need 6 moles of oxygen for every 1 mole of glucose).

The energy release for 0.5 mol of glucose is:

(2803 kJ/mol) / 1 mol glucose x 0.5 mol glucose = 1401.5 kJ

To convert this to kcal, we divide by 4.184:

1401.5 kJ / 4.184 kJ/kcal = 334.7 kcal

Rounding to the nearest tenth gives the final answer of 335.3 kcal, which is choice B.

The Combustion of Glucose (C6H12O6) with Oxygen Gas Produces Carbon

The Combustion of Glucose (C₆H₁₂O₆) with Oxygen Gas Produces Carbon