How many sodium ions are present in 325 mL of 0.850 M Na₂SO₄?

Question

Quizplus · Accepted Answer

First, we need to find the molar concentration of sodium ions in the given solution. The compound Na₂SO₄ dissociates into Na+ and (S2O3)2- ions in aqueous solution. The molar mass of Na₂SO₄ is 248.18 g/mol. To find the number of moles present in 325 mL of 0.850 M Na₂SO₄, we can use the formula: moles = concentration (in M) x volume (in L) moles of Na₂SO₄ = 0.850 x 0.325 = 0.27625 mol Since Na₂SO₄ contains one Na+ ion per molecule, the number of moles of Na+ ions will be the same as the number of moles of Na₂SO₄. So, the number of moles of Na+ ions = 0.27625 mol To find the number of ions, we can use Avogadro's number: Number of Na+ ions = moles x Avogadro's number Number of Na+ ions = 0.27625 x 6.022 x 10^23 = 1.662 x 10^23 Therefore, the answer is B, 3.33 × 10^23 sodium ions.

How Many Sodium Ions Are Present in 325 ML of 0.850