A 0.00100 mol sample of Ca(OH)₂ requires 25.00 mL of aqueous HCl for neutralization according to the reaction below. What is the concentration of the HCl? Equation: Ca(OH)₂(s) + 2HCl(aq) → CaCl₂(aq) + H₂O(l)

Question

Quizplus · Accepted Answer

From stoichiometry, we know that 1 mole of Ca(OH)2 reacts with 2 moles of HCl. Therefore, the 0.00100 mol of Ca(OH)2 will require 0.00200 mol of HCl for neutralization.

We can calculate the concentration of HCl using the formula:

molarity = moles of solute / liters of solution

Since we were given the volume of HCl as 25.00 mL, we need to convert it to liters:

25.00 mL = 0.02500 L

Now we can calculate the concentration of HCl:

molarity = 0.00200 mol / 0.02500 L = 0.0800 M

Therefore, the correct answer is choice C.

A 000100 Mol Sample of Ca(OH)2 Requires 25

A 000100 Mol Sample of Ca(OH)₂ Requires 25