Magnesium (used in the manufacture of light alloys) reacts with iron(III) chloride to form magnesium chloride and iron. 3Mg(s) + 2FeCl3(s) → 3MgCl2(s) + 2Fe(s) A mixture of 41.0 g of magnesium (
= 24.31 g/mol) and 175 g of iron(III) chloride (
= 162.2 g/mol) is allowed to react. Identify the limiting reactant and determine the mass of the excess reactant present in the vessel when the reaction is complete.
A) Limiting reactant is Mg; 67 g of FeCl3 remain.
B) Limiting reactant is Mg; 134 g of FeCl3 remain.
C) Limiting reactant is Mg; 104 g of FeCl3 remain.
D) Limiting reactant is FeCl3; 2 g of Mg remain.
E) Limiting reactant is FeCl3; 87 g of Mg remain.
Correct Answer:
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