What is the [OH-] for a solution at 25°C that has [H₃O⁺] = 2.35 × 10^-3 M?

Question

Quizplus · Accepted Answer

We can use the equation for the ion product of water to find the [OH-]: Kw = [H+][OH-] = 1.0 × 10^-14 at 25°C Since the solution in question is neutral (not acidic or basic), the [H+] and [OH-] concentrations must be equal: [H+] = [OH-] Therefore, we can use the given concentration of [H₃O⁺] as the [H+] concentration: [H+] = 2.35 × 10^-3 M Substituting into the ion product of water equation and solving for [OH-]: Kw = [H+][OH-] 1.0 × 10^-14 = (2.35 × 10^-3)([OH-]) [OH-] = 4.26 × 10^-12 M Therefore, the answer is C: 4.26 × 10^-12 M.

What Is the [OH-] for a Solution at 25°C That