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About Half of the Sodium Carbonate Produced Is Used in Making

Question 31

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About half of the sodium carbonate produced is used in making glass products because it lowers the melting point of sand, the major component of glass. When sodium carbonate is added to water it hydrolyses according to the following reactions. CO32-(aq) + H2O(l) About half of the sodium carbonate produced is used in making glass products because it lowers the melting point of sand, the major component of glass. When sodium carbonate is added to water it hydrolyses according to the following reactions. CO<sub>3</sub><sup>2-</sup>(aq) + H<sub>2</sub>O(l) HCO<sub>3</sub><sup>-</sup>(aq) + OH<sup>-</sup>(aq) K<sub>1</sub> HCO<sub>3</sub>(aq) + H<sub>2</sub>O(l) H<sub>2</sub>CO<sub>3</sub>(aq) + OH<sup>-</sup>(aq) K<sub>2</sub> These can be combined to yield CO<sub>3</sub><sup>2-</sup>(aq) + 2H<sub>2</sub>O(l) H<sub>2</sub>CO<sub>3</sub>(aq) + 2OH<sup>-</sup>(aq) K<sub>3</sub> What is the value of K<sub>3</sub>? A) K<sub>1</sub> × K<sub>2</sub> B) K<sub>1</sub> ÷ K<sub>2</sub> C) K<sub>1</sub> + K<sub>2</sub> D) K<sub>1</sub> - K<sub>2</sub> E) (K<sub>1</sub>K<sub>2</sub>) <sup>2</sup> HCO3-(aq) + OH-(aq) K1
HCO3(aq) + H2O(l) About half of the sodium carbonate produced is used in making glass products because it lowers the melting point of sand, the major component of glass. When sodium carbonate is added to water it hydrolyses according to the following reactions. CO<sub>3</sub><sup>2-</sup>(aq) + H<sub>2</sub>O(l) HCO<sub>3</sub><sup>-</sup>(aq) + OH<sup>-</sup>(aq) K<sub>1</sub> HCO<sub>3</sub>(aq) + H<sub>2</sub>O(l) H<sub>2</sub>CO<sub>3</sub>(aq) + OH<sup>-</sup>(aq) K<sub>2</sub> These can be combined to yield CO<sub>3</sub><sup>2-</sup>(aq) + 2H<sub>2</sub>O(l) H<sub>2</sub>CO<sub>3</sub>(aq) + 2OH<sup>-</sup>(aq) K<sub>3</sub> What is the value of K<sub>3</sub>? A) K<sub>1</sub> × K<sub>2</sub> B) K<sub>1</sub> ÷ K<sub>2</sub> C) K<sub>1</sub> + K<sub>2</sub> D) K<sub>1</sub> - K<sub>2</sub> E) (K<sub>1</sub>K<sub>2</sub>) <sup>2</sup> H2CO3(aq) + OH-(aq) K2
These can be combined to yield
CO32-(aq) + 2H2O(l) About half of the sodium carbonate produced is used in making glass products because it lowers the melting point of sand, the major component of glass. When sodium carbonate is added to water it hydrolyses according to the following reactions. CO<sub>3</sub><sup>2-</sup>(aq) + H<sub>2</sub>O(l) HCO<sub>3</sub><sup>-</sup>(aq) + OH<sup>-</sup>(aq) K<sub>1</sub> HCO<sub>3</sub>(aq) + H<sub>2</sub>O(l) H<sub>2</sub>CO<sub>3</sub>(aq) + OH<sup>-</sup>(aq) K<sub>2</sub> These can be combined to yield CO<sub>3</sub><sup>2-</sup>(aq) + 2H<sub>2</sub>O(l) H<sub>2</sub>CO<sub>3</sub>(aq) + 2OH<sup>-</sup>(aq) K<sub>3</sub> What is the value of K<sub>3</sub>? A) K<sub>1</sub> × K<sub>2</sub> B) K<sub>1</sub> ÷ K<sub>2</sub> C) K<sub>1</sub> + K<sub>2</sub> D) K<sub>1</sub> - K<sub>2</sub> E) (K<sub>1</sub>K<sub>2</sub>) <sup>2</sup> H2CO3(aq) + 2OH-(aq) K3
What is the value of K3?


A) K1 × K2
B) K1 ÷ K2
C) K1 + K2
D) K1 - K2
E) (K1K2) 2

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