The following reaction is at equilibrium at one atmosphere, in a closed container. NaOH(s) + CO₂(g) NaHCO₃(s)
Which, if any, of the following actions will decrease the total amount of CO₂ gas present at equilibrium?

Question

The following reaction is at equilibrium at one atmosphere, in a closed container. NaOH(s) + CO₂(g)

The following reaction is at equilibrium at one atmosphere, in a closed container. NaOH(s) + CO<sub>2</sub>(g) NaHCO<sub>3</sub>(s) Which, if any, of the following actions will decrease the total amount of CO<sub>2</sub> gas present at equilibrium? A) adding N<sub>2</sub> gas to double the pressure B) adding more solid NaOH C) decreasing the volume of the container D) removing half of the solid NaHCO<sub>3</sub> E) None of these choices are correct.

NaHCO₃(s)
Which, if any, of the following actions will decrease the total amount of CO₂ gas present at equilibrium?

Quizplus · Accepted Answer

According to Le Chatelier's principle, when the volume of a closed container is decreased, the gas molecules will be forced closer together, which increases the pressure. In this case, decreasing the volume of the container will increase the pressure, which will shift the equilibrium to favor the side with fewer gas molecules, leading to a decrease in the total amount of CO₂ gas present. Adding more N₂ gas, adding more solid NaOH, or removing half of the solid NaHCO₃ will not affect the amount of CO₂ gas present because these changes do not directly affect the pressure or concentration of CO₂ gas in the system.

The Following Reaction Is at Equilibrium at One Atmosphere, in a Closed